Question

set builder form of

a ) {-1 , 1}

and

b ) { 15 , 24 , 33 , 42 , 51 , 60 }

plz find it...plz

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Answer 1

Answer:

A={a I a is root of the equation a^2 =1}.

because in

x^2 =1 to find the value of x we need to take square root both the sides,

$\sqrt{a^{2} } =\sqrt{1}$

∴a±1

so a = 1 or a =-1

Let the two-digit number b is of the form b=xy. This states that 15 can be written as x=1,y=5.

the sum of two-digit number 15 is 6:

⇒ 1+5=6

the sum of two-digit number 24 is 6:

⇒2+4=6

the sum of two-digit number 33 is 6:

⇒3+3=6

the sum of two-digit number 42 is 6:

⇒4+2=6

the sum of two-digit number 51 is 6:

⇒5+1=6

the sum of two-digit number 60 is 6:

⇒6+0=6

Therefore, from the above calculations it can be concluded that the set builder form of B is  B={b|b is a two digit number having sum of digits is 6}