Question

Set builder form of the relation
R = {(-2, -7), (-1, -4), (0, -1), (1, 2), (2, 5)} is
(a) {(a, b) : b = 2a - 3; a, b, ∈ Z}
(b) {(x, y) : y = 3x - 1; x, y, ∈ Z}
(c) {(a, b) : b = 3a - 1; a, b, ∈ N}
(d) {(u, ????) : ???? = 3u = 1; -2 ≤ u < 3 and u ∈ Z}

Answer 1

Answer:

Hey there mate, the answer should be - (b)

Step-by-step explanation:

Let us first observe option (a)

It's given that b = 2a - 3

Now, let's take a = -2 and put it in the above relation    [from relation,R]

So, we get     b = 2 x (-2) - 3

                       = -4 - 3

                       = -7

Again, let us check the next one where a = -1

We get          b = 2 x(-1) - 3

                       = -2-3

                       = -5        

i.e. in the next one b ≠ -4  

So, option a is wrong.

Similarly let us follow the same procedure with option (b)

Taking x = -2, y = 3(-2) - 1

                        = -7

Again, x = -1,   y =3(-1) - 1

                        = -4

check the other one's too by yourself and see if the relation is correct.

Hope this helps you dear.

                        WISH YOU LUCK!!  

Answer 2

Answer:

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