Set builder form:write in set builder form 1,5,10,15
Answers
Answered by
35
(x: x€N such that x = 1,x=5n for n<=3)
Answered by
17
Answer:
A = { P :P = 5n where n<3}
Step-by-step explanation:
Given : Set 1,5,10,15
To find : Write in set builder form 1,5,10,15?
Solution :
Let A be the set A={1,5,10,15}
We have seen that the above set is the multiple of 5.
So, The equation satisfying this set is P=5n, n is the natural number and n<3
Put n=1 , P=5
Put n=2, P=10
Put n=3, P=15
A = { 1 , 5 , 10, 15} in set builder form is
A = { P :P = 5n where n<3}
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