set of 2 digit numbers the sum of whose digit is 8
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Let's set one of the digits to 0, the 2 numbers possible are 08 and 80, but as 08 is a one digit number, we omit it and count 80.
Then, fix 1 as one of the digits- the 2 numbers possible are 17 and 71.
Then fix 2 as one of the digits- the 2 numbers possible are 26 and 62.
Carrying on in this way, we have the following numbers which satisfy the criterion- 80, 17, 71, 26, 62, 35, 53, 44. There are 8 such numbers.
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