Question

set of solution of the quadratic eqn x^2 +5x+6=0​

Answer 1

Step-by-step explanation:

solution: x^2+(3+2)x+6=0

= x^2+3x+2x+6=0

= x(x+3)+2(x+3)=0

= (x+3) (x+2)

now, and,

x+3=0. x+2=0

x= -3. x=-2

Answer 2

GIVEN:-

$\large{\sf{{x}^{2}+5x+6=0}}$

TO FIND:-

Set of solution of the quadratic equation.

SOLUTION:-

$\large\Rightarrow{\sf{{x}^{2}+5x+6=0}}$

By splitting the middle term,

$\large\Rightarrow{\sf{{x}^{2}+(2x+3x)+6=0}}$

$\large\Rightarrow{\sf{x(x+2)+3(x+2)=0}}$

$\large\Rightarrow{\sf{(x+3)(x+2)=0}}$

$\large\therefore{\sf{x+3=0}}$

$\large\therefore\boxed{\sf{x=-3}}$

and,

$\large\therefore{\sf{x+2=0}}$

$\large\therefore\boxed{\sf{x=-2}}$

$\large{\pink{\boxed{\underline{\therefore{\sf{{x=-3\:or\:x=-2.}}}}}}}$