Question

set of the positive real roots of the equation x cube -2x square-x+2=0​

Answer 1

Answer:

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Step-by-step explanation:

The given equation is:

y=x

3

−3x+k

⇒y

′

=3x

2

−3

y

′

=0

⇒3x

2

−3=0

⇒x=±1. Thus the stationary points being +1 and −1 they lie outside the given region hence no value of k can make the equation roots lie in the given range of (0,1). ....Answer

Answer 2

Answer:

...1;

....-1

...2

there is three roots