Question

Set of values of x, if
$\sqrt{(x+8)} +\sqrt{(2x+2)} =1$

Answer 1

$\huge{\dag} \: {\underline{\boxed{\sf{\pink{ Answer }}}}}$

$ㅤㅤㅤㅤㅤ \mathsf{squaring \: both \: sides}$

$\implies \mathsf{(x + 8 )^{2} + (2 {x} + 2)^{2} = {1}^{2} }$

$\implies \mathsf{ ({x}^{2} + 16x + 64) + (4 {x}^{2} + 8x + 4) = 1}$

$\implies \mathsf{5 {x}^{2} + 24x + 68 - 1 = 0 }$

$\implies \mathsf{5 {x}^{2} + 24x + 67 = 0}$

$\implies \mathsf{solving \: quadratic \: equation}$

$\implies \mathsf{refer \: attachment}$

writting samaj lena jldi jldi me likha hai ...xD

Answer 2

jaldi jaldi likha hai writing samajh lena..xdxd