Sethu travelled (4x²+3xy²+5x) kilometre in‘2x’ hours. Find his speed of travel
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Distance = 4x² + 3xy² + 5x
Time = 2x
= 4x² + 3xy² + 5x / 2x
= 4x²/2x + 3xy²/2x + 5x/2x
= 2x + 3y²/2 + 5/2
= 2x + 1½y² + 2½ km/h
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