Math, asked by Topperworm, 1 year ago

Sets topic question
Calculate x

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Answers

Answered by siddhartharao77
13

Step-by-step explanation:

Given:\frac{(x - 13)^2 * (x + 13)^2}{x - 1} < 0

Step (i):

(x - 13)² = 0

=> x = 13

(b) (x - 13)² > 0

=> x < 13 (or) x > 13

Step (ii)

(a) (x + 13)² = 0

x = -13

(b) (x + 13)² > 0

x < -13 (or) x > -13

Step (iii):

x - 1 = 0

x = 1

Table:

              x < -13      x = -13     -13<x<1   x = 1   1<x<13  x = 13  x > 13

(x - 13)       +             +                +           +          +        0         +

(x + 13)       +             0               +            +          +         +         +

x - 1            -              -                -             0          +         +         +  

Now,

We have to identify the intervals that satisfy the condition < 0.

Solution : x < -13 (or) - 13 < x < 1

Interval : (-∞, -13) ∪ (-13,1)

Hope it helps!


Topperworm: Thank u so much
siddhartharao77: Welcome dear
Answered by kiara123
0

step-by-step explanation:❤

Given:\frac{(x - 13)^2 * (x + 13)^2}{x - 1} < 0Given:

x−1

(x−13)

2

∗(x+13)

2

<0

Step (i):

(x - 13)² = 0

=> x = 13

(b) (x - 13)² > 0

=> x < 13 (or) x > 13

Step (ii)

(a) (x + 13)² = 0

x = -13

(b) (x + 13)² > 0

x < -13 (or) x > -13

Step (iii):

x - 1 = 0

x = 1

Table:

x < -13 x = -13 -13<x<1 x = 1 1<x<13 x = 13 x > 13

(x - 13) + + + + + 0 +

(x + 13) + 0 + + + + +

x - 1 - - - 0 + + +

Now,

We have to identify the intervals that satisfy the condition < 0.

Solution : x < -13 (or) - 13 < x < 1

Interval : (-∞, -13) ∪ (-13,1)

Hope it helps....

Kiara

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