Math, asked by shala67, 4 hours ago

Seven blank spaces, which are numbered from 1 to 7, are arranged in a row in ascending order from left to
right. Two A's three B's and two C's are to be filled in these seven blank spaces such that the same
alphabet never consecutive blank spaces. In how many ways can this be done if B is always filled in the first
blank space?​

Answers

Answered by sdeepikas827
0

Answer:

two A's three B's and c's

Step-by-step explanation:

i

Answered by amitnrw
1

Given :  Seven blank spaces, which are numbered from 1 to 7, are arranged in a row in ascending order from left to right.

Two A's three B's and two C's are to be filled in these seven blank spaces such that the same alphabet never consecutive blank spaces  

To Find :  In how many ways can this be done if B is always filled in the first

blank space

Solution:

As B is 1st Hence

BA   or BC   is   only possible

considering BA cases   then BAB or BAC is possible

     BAB                                

 BABA           BABC            

 BABACBC  BABCABC , BABCACB , BABCBAC , BABCBCA

 BAC        

BACA   BACB

BACABCB     BACBACB  ,   BACBABC  , BACBCAB  ,BACBCBA

Considering BC cases   then BCA or BCB is possible

BCA

BCAB  , BCAC

BCACBAB  ,  BCABABC , BCABACB , BCABCAB , BCABCBA

BCB

BCBA , BCBC

BCBCABA  , BCBABAC ,  BCBABCA , BCBACAB ,  BCBACBA

Hence total 20 possible

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