SEVEN FRIENDS WENT FOR A HIKING TRIP . EACH CARRIED A SEPARATE BAG OF 9 WHOLE 3 UPON 4 KG OF WHEAT 7WHOLE 3 UPON 4 KG OF RICE AND 5 WHOLE 1 UPON 4 KG OF PROVISIONS THEY GOT A MAN HELP THEM CARRY THE BAGS BUT HE COULD CARRY A MAXIMUM WEIGHT OF 105KG THE FRIENDS DECIDED TO ASK THE MAN TO CARRY THE BAGS AND ALSO DECIDED THAT EACH OF THEM WILL CARRY ONE OF THEIR BAGS WHICH OF THE THREE BAGS WILL EACH ONE OFTHEM HAVE TO CARRY ? WHY?
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WE CHANGE THIS ALL IN GRAMS AND DO AS FOLLOWS
A/Q
> WHEAT total weight =39/4*1000=9750 grams weight of 1 bag
> RICE tatal weight =31/4*1000=7750 grams weight of 1 bag
> PROVISIONS = 21/4*1000=5250 grams weight of 1 kg
a/q one bag they should carry that is of rice because the sum of 7 bags of wheat and provisions =105 kg =105000 grams
A/Q
> WHEAT total weight =39/4*1000=9750 grams weight of 1 bag
> RICE tatal weight =31/4*1000=7750 grams weight of 1 bag
> PROVISIONS = 21/4*1000=5250 grams weight of 1 kg
a/q one bag they should carry that is of rice because the sum of 7 bags of wheat and provisions =105 kg =105000 grams
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