Seven girls anita, babita, charita, kavita, ruchita, sarita and sunita sitting in a row facing north, not necessarily in the same order. (i) sarita sits to the left of babita. (ii) kavita and sunita are not adjacent to each other. (iii) babita sits adjacent to kavita and charita. (iv) sunita sits at an end. (v) anita sits second to the left of ruchita and is at an end.
Answers
Answer:
The sequence of their seating arrangement starting from the left to the right of the row( facing north) is as follows-
(Extreme left end) Anita, Sarita, Ruchita, Kavita, Babita, Charita, Sunita( extreme right end)
Step-by-step explanation:
This can be solved by first placing the corner members.
As given, Anita is at one extreme end and is second to the left of Ruchita so it is very clear that Anita is at the left extreme end.
Therefore, Sunita is at the right extreme end.
The rest of the members are placed by following the rest of the conditions.
Answer:
ANITA SARITA RUCHITA KAVITA BABITA CHARITA SUNITA
Step-by-step explanation:
Seven girls anita, babita, charita, kavita, ruchita, sarita and sunita sitting in a row facing north, not necessarily in the same order. (i) sarita sits to the left of babita. (ii) kavita and sunita are not adjacent to each other. (iii) babita sits adjacent to kavita and charita. (iv) sunita sits at an end. (v) anita sits second to the left of ruchita and is at an end.
ANITA SARITA RUCHITA KAVITA BABITA CHARITA SUNITA
Let say count 1 - 7 from Left to right
anita sits second to the left of ruchita and is at an end.
Anita is in left of ruchita and is at an end
=> Anita at position 1 ( left end)
& Ruchita at position 3
Sunita sits also at an end
so Sunita at position 7 (right end)
babita sits adjacent to kavita and charita
=> Babita , Kavita & Charita all are together
remaining positions are 2 , 4 , 5 , 6
=> Babita , Kavita & Charita will be at 4 , 5 , 6
& Babita will be at 5
kavita and sunita are not adjacent to each other
=> kavita can not be at 6
=> Kavita will be at 4
& Charita will be at 6
Sarita is left to babita & only position left is 2
=> Sarita at position 2
1 2 3 4 5 6 7
ANITA SARITA RUCHITA KAVITA BABITA CHARITA SUNITA