Question

Seven resistors each of resistance 7 ohm are connected across a 14 V battery as shown below. Choose the incorrect statement among the following.
(1) Voltage drop across resistor R1 is 7 V
(2) Current flowing through resistors R3, and R5 is
(3) Current flowing through resistor R4 is 1 A
(4) Net power dissipated in the circuit is 70 W​

Answer 1

Answer:

Here incorrect statement is

(3) Current flowing through resistor R4 is 1 A

Explanation:

As per the figure we know that R2 and R3 is parallel as we as R5 and R6 is parallel

now we have

$R_{23} = R_{56} = \frac{R_5 R_6}{R_5 + R_6}$

$R_{23} = R_{56} = \frac{R}{2}$

Now we have

$R_{125} = R_1 + R_{23} + R_{56}$

$R_{125} = 7 + \frac{7}{2} + \frac{7}{2}$

so we have

$R_{125} = 14 ohm$

now total voltage drop in R1 resistance is given as

$V_1 = R_1 i$

$V_1 = 7(\frac{14}{14} = 7 V$

Now total current in R125 is divided equally in R3 and R5

so its current is

$i = \frac{1}{2}\frac{V}{R_{125}$

$i = 0.5 A$

Current through resistance R4

$i = \frac{V}{R_4}$

$i = \frac{14}{7} = 2 A$

Total resistance of the circuit is given as

$\frac{1}{R} = \frac{1}{14} + \frac{1}{7} + \frac{1}{7}$

$R = \frac{14}{5}$

now we have

$P = \frac{V^2}{R}$

$P = \frac{14^2}{14/5} = 70 W$

#Learn

Topic : electric circuits

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