Question

seven students wearing medals 1,2,3,4,5,6,7 are seated on 7 circular table.in how many ways can they be seated so that no any student having consecutive medal no. can be seated together ?

Answer 1

Answer:

7,6,5,3,3,2,1

Step-by-step explanation:

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Answer 2

Question :- seven students wearing medals 1,2,3,4,5,6,7 are seated on 7 circular table.in how many ways can they be seated so that no any student having consecutive medal no. can be seated together ?

Solution :-

it has been given that, no student having consecutive medal no. can be seated together .

That means, 1 and 2 cant sit together .

Example :- 1, 3, 5, 7 , 2, 4, 6 . ( Here No consecutive numbers are together.)

Now,

we know that, total number of ways in which n students can sit in a circular table is (n - 1)! .

Given that, n = 7

So,

→ Total number of ways = (7 - 1)! = 6! = 6*5*4*3*2 = 720 ways.

Now, since no two students with consecutive medals can sit together.

Therefore,

→ Required Number of ways = (720/2) = 360 ways. (Ans.)