Question

Seven times a given two digit number is equal to four times the number obtained by
reversing the order of digits. The sum of the digits of the number is 3. Find the number.

Answer 1

let numbers be x at ones place and y at tens place so

10y+x is that digit

now reversed digit is 10x+y

according to question

7 (10y+x)=4(10x+y)

x=2y (i)

now

given

x-y=3

from eq. i 2y=x

2y-y=3

y=3

so

x=63

required original no. is 36 and reversed digit is 63

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Answer 2

Answer:

12

Step-by-step explanation:

12*7=84

1+2=3

12 (reverse)=21

21*4=84

Hence, your answer is 12

Hope it helps