Question

Seven times a given two digit number is equal to four times the number obtained by reversing the order of digits. The sum of the digits of number is 3.Find the number​

Answer 1

Answer:

Let first digit of two digit number is x and second digit is y.

As per the question

7xy = 4yx

And difference between two digits is 3 i.e

x-y = 3

Get thw value of y from this equation

Y = x -3

Put this value of y in 7xy =4yx

7x (x-3) = 4x (x-3)

7x ^2 - 21x = 4x^2 - 12x

3x^2 = 9x

3x = 9

x = 3

Now put the value of x in Y =x-3

So the value of y is 0

The two digit number is 30.

Answer 2

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let numbers be x at ones place and y at tens place so

10y+x is that digit

now reversed digit is 10x+y

according to question

7 (10y+x)=4(10x+y)

x=2y (i)

now

given

x-y=3

from eq. i 2y=x

2y-y=3

y=3

so

x=63

required original no. is 36 and reversed digit is 63

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