Question

Seven times a given two digit number is equal to four times the number obtained by reversing the order of digits. The sum of the digits of the number is 3. Find the number.​

Answer 1

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Let the digit at the unit's place and tens place be x and y respectively.

↪The original number=10y+x

↪ Reversed=10x+y

Now, according to the question

7(10y+x)=4(10x+y)

70y+7x=40x+4y

70y-4y=40x-7x

66y=33x

2y=x-------(1)

Also, the sum of the digits is 3,

x+y=3------(2)

Substituting (1) in (2),

2y+y=3

3y=3

➡y=1

Substituting y=1 in (1),

2(1)=x

➡x=2

Thus, the number will be:

10y+x=10(1)+2=12

Answer:12

Answer 2

Answer:

36

Step-by-step explanation:

Let the unit digit be a and tenth unit be b .

So , number = 10 b + a

It's said number is seven times is equal to reversing the order of its digit.

= > 7 ( 10 b + a ) = 4 ( 10 a + b )

= > 70 b + 7 a = 40 a + 4 b

= > 66 b = 33 a

= > a = 2 b ... ( i )

Also given numbers' difference is 3 .

a - b = 3  ( ii )

From ( i ) and ( ii ) we get :

a b - b = 3

b = 3

= > a = 6

Hence number = > 30 + 6

= > 36.