seven times a two digit no. is equal to four times the number formed by reversing the digits. the sum of the digits of the no. is 3 . find the number.
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LET THE DIGIT AT TEN" S PLACE BE X & UNIT"S PLACE BE Y
REQ. ORIGINAL NO. = 10X+Y REVERSED NO. =10Y+X
ALSO Y - X = 3 => Y = 3 +X
A/Q, 7(10X+Y) = 4 (10Y+X)
=> 7( 11X + 3) = 4( 30 +11X)
=>77X -44X = 120 -21
=> 33 X =99
=> X = 3 & Y= 3 +X = 3 +3 = 6
REQ. ORIGINAL NO. = 10X+Y = 10 * 3 +6 = 36...................
REQ. ORIGINAL NO. = 10X+Y REVERSED NO. =10Y+X
ALSO Y - X = 3 => Y = 3 +X
A/Q, 7(10X+Y) = 4 (10Y+X)
=> 7( 11X + 3) = 4( 30 +11X)
=>77X -44X = 120 -21
=> 33 X =99
=> X = 3 & Y= 3 +X = 3 +3 = 6
REQ. ORIGINAL NO. = 10X+Y = 10 * 3 +6 = 36...................
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