Seven times a two digit number equal four times the number with digit reversed find the number if the sum of its digit is 3
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let the ones digit is x, and tenth digit is y. then the number will be 10x+y.
If we reverse their positions then the number will be 10y+x.
We know 7(10x+y)=4(10y+x)
=>70x+7y = 40y+x
=> 66x=33y
=> 2x=y
but x+y=3
x+2x=3
x=1 & y=2
the numbers are 12 and 21
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