Question

SEVEN TIMES A TWO DIGIT NUMBER IS EQUAL TO FOUR TIME THE NUMBER OBTAINED BY REVERSING THE ORDERS OF ITS DIGITS .IF THE DIFFERNCE OF THE DIGIITS IS 3 DETERMINE THE NUMBER

Answer 1

The number is 36. You can solve it by taking units digit as x+3 and tens unit as x. Then the number shall be as (10x+x+3) =11x+3. Then solve the equation,
7(11x+3) = 4[10(x+3)+x]
You can also solve it by two variable too.

Answer 2

Answer:

36

Step-by-step explanation:

Let the unit digit be a and tenth unit be b .

So , number = 10 b + a

It's said number is seven times is equal to reversing the order of its digit.

= > 7 ( 10 b + a ) = 4 ( 10 a + b )

= > 70 b + 7 a = 40 a + 4 b

= > 66 b = 33 a

= > a = 2 b ... ( i )

Also given numbers' difference is 3 .

a - b = 3  ( ii )

From ( i ) and ( ii ) we get :

a b - b = 3

b = 3

= > a = 6

Hence number = > 30 + 6

= > 36.