seven times a two digit number is equal to four time times the number obtained by reversing the order of its digits. if the difference of the digit is 3, determine the numbers.
Answers
Answered by
1
Solution
Suppose x is digit in ten's place and y is the digit in unit's place.
So the number 10x+y
By reversing the order of the digits, the new Number is 10y+x
According to the given condition 7(10x+y)=4(10y+x)
Also x-y=3
Solve
number is 36
dubeysatyajeetc:
Hey friend..... The number is -36 not 36
You can refer the working above (in my solution)
Answered by
3
let the once digit = y
let the tens digit = 10x
7(10x + y) = 4(10y+x)
70x + 7y = 40y + 4x
70x - 4x -40y + 7y = 0
66x - 33y =0 ( dividing by 33)
2x - y = 0
x - y = 3
-. +
x = -3
y = 3- x
y= -6
number is -36
let the tens digit = 10x
7(10x + y) = 4(10y+x)
70x + 7y = 40y + 4x
70x - 4x -40y + 7y = 0
66x - 33y =0 ( dividing by 33)
2x - y = 0
x - y = 3
-. +
x = -3
y = 3- x
y= -6
number is -36
let the two digits be x and y
> the number (original) = 10x + y
> the number (reverse) = 10y + x
according to the question:
> 7 ( 10x + y ) =4 ( 10y + x )
70x + 7y = 40y + 4x
66x - 33y = 0
2x - y = 0 [divided by 33]
> x - y = 3
x = 3 + y
SOLUTION
2 ( 3 + y ) - y = 0
6 + 2y - y = 0
y = -6
x = 3 + y
= 3 - 6
=-3
The number (original) = -36
The number (reverse) = -63
> the number (original) = 10x + y
> the number (reverse) = 10y + x
according to the question:
> 7 ( 10x + y ) =4 ( 10y + x )
70x + 7y = 40y + 4x
66x - 33y = 0
2x - y = 0 [divided by 33]
> x - y = 3
x = 3 + y
SOLUTION
2 ( 3 + y ) - y = 0
6 + 2y - y = 0
y = -6
x = 3 + y
= 3 - 6
=-3
The number (original) = -36
The number (reverse) = -63
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