Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits. If the difference of the digits is 3 determine the numbee
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Hi ☺☺
Your Answer....
➡Let the ten's place digit of two digit no. be x
and unit's place digit be y
Then Number is 10x+y
Number when digit is reverse is 10y+x
ATQ,
Difference between digit is 3,
y-x = 3
=> y = x+3
And,
7(10x+y) = 4(10y+x)
70x+7y = 40y+4x
=> 66x = 33y
=> 2x = y
=> 2x = x+3
=> x = 3
=> y = 6
Hence The Number is 36..☺☺
Your Answer....
➡Let the ten's place digit of two digit no. be x
and unit's place digit be y
Then Number is 10x+y
Number when digit is reverse is 10y+x
ATQ,
Difference between digit is 3,
y-x = 3
=> y = x+3
And,
7(10x+y) = 4(10y+x)
70x+7y = 40y+4x
=> 66x = 33y
=> 2x = y
=> 2x = x+3
=> x = 3
=> y = 6
Hence The Number is 36..☺☺
Answered by
0
Seven times a given two digit number is equal to four times the number obtained by inter changing the digits
7(10x+y)=4(x+10y)
70x+7y=4x+40y
66x-33y=0
2x-y=0
2x=y
The difference of the digits is 3
y-x=3
2x-x=3
x=3
y=6
that number is 36.
7(10x+y)=4(x+10y)
70x+7y=4x+40y
66x-33y=0
2x-y=0
2x=y
The difference of the digits is 3
y-x=3
2x-x=3
x=3
y=6
that number is 36.
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