Question

Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits. If the differences of the digits is 3, determine the number

Answer 1

Solution

Suppose x is digit in ten's place and y is the digit in unit's place. 
So the number 10x+y
By reversing the order of the digits, the new Number is 10y+x
According to the given condition 7(10x+y)=4(10y+x)
Also x-y=3
Solve 
number is 36

Answer 2

Answer:

36

Step-by-step explanation:

Let the unit digit be a and tenth unit be b .

So , number = 10 b + a

It's said number is seven times is equal to reversing the order of its digit.

= > 7 ( 10 b + a ) = 4 ( 10 a + b )

= > 70 b + 7 a = 40 a + 4 b

= > 66 b = 33 a

= > a = 2 b ... ( i )

Also given numbers' difference is 3 .

a - b = 3  ( ii )

From ( i ) and ( ii ) we get :

a b - b = 3

b = 3

= > a = 6

Hence number = > 30 + 6

= > 36.