Question

seven times a two digit number is equal to four times the number obtained by reversing the order of its digits if the difference of the digit is 3 determine the number

Answer 1

Let the number be
x+10y.................(1)

Given:
7(x+10y)=4(y+10x)
7x+70y=4y+40x
70y-4y=40x-7x
66y=33x
x=66y/33
x=2y.................(2)
&
x-y=3
from (2)
2y-y=3

y=3

and
x-y=3
x-3=3
x=3+3
x=6


now
number will be
x+10y
6+10(3)
6+30
=36

HOPE IT WILL HELP YOU PLZZ MARK IT AS BRAINLIEST

Answer 2

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Hey Mate !!

Here's your answer !!

Let the two digit number be 10x + y

Number obtained by reversing its digits be 10y + x

Let the larger digit be y and smaller digit be x

Given:

= y - x = 3 -----------(1)

= 7 ( 10x + y ) = 4 ( 10y + x )

= 70x + 7y = 40y + 4x

= 70x - 4x  = 40y - 7y

= 66x = 33y

= 2x = y -----(2)

Substitute (2) in (1)

= y - x = 3

= 2x - x = 3

= x =3

=> y = 3 + x

= y = 3 + 3

= y = 6

Hence the original number is ( 10x + y)

= ( 10 × 3 + 6)

= ( 30 + 6 )

= 36

Hence the number to be determined is 36

Hope this helps !!

Cheers !! 
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# Kalpesh :)