Question

Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits. If the difference of the digits is 3, determine the number.

Answer 1

Let the tens place digit be a

And Unit place digit be b

According to first condition,

7( 10a + b) = 4( 10b + a)

=> 70a + 7b = 40b + 4a

=> 66a = 33b

=> b = 2a

Now,

According to second condition,

b - a = 3

=> 2a - a = 3

=> a = 3

b = 6

Required number = 36

Answer 2

solution......

let the ten's place digit be x
and units digit's place b y ..

case 1: 7(10x+y)=4(10y+x)
70x+7y=40y+4x
66x=33y
y=2x


case2: y-x=3
2x-x=3
x=3

y=6


hence, the required number is 36...


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