Question

Seven times a two-digit number is equal to four times the number obtained by reversing the

order of its digits. If the difference between the digits is 3, find the number.​

Answer 1

Answer:

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so here we go

Step-by-step explanation:

let the two digit number be 10x+y

wherein digit at units place be y and that of tens be x

so number obtained by reversing digits is 10y+x

so according to first condition

7(10x+y)=4(10y+x)

so 70x+7y=40y+4x

so 66x=33y

ie 2x=y (1)

so now we can conclude that y is greater than x from (1)

according to second condition

y-x=3 (2)

substitute value of y in (2) from (1)

ie 2x-x=3

ie x=3

substitute value of x in (1)

we get

y=6

so our two digit number was 10x+y

10x+y=(10×(3))+(6)

ie 30+6

=36

so our required two digit number is 36 and the reversed number is 63

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