Question

Seven times a two - digit number is equal to four times the number obtained by reversing the digits. If the difference between the digit is 3. Find the number.

Answer 1

let the tens digit be x then the unit digit be x+3
the original no. is 10*x + x+3 = 11x + 3
on reversing the digit the new no. is 10(x+3) + x = 11x + 30
7(11x+3 ) = 4(11x+30)
=> 77x + 21 = 44x + 120
=> 77x - 44x = 120-21
=> 33x = 99
=> x = 3
the no. is 11*3 + 3 = 36
hope it helps u plz mark as brainliest

Answer 2

Question

Seven times a two-digit number is equal to four times the number obtained by reversing the digits. If the difference between the digits is 3. Find the number.

Solution

Assume the ones digit as x and tens digit as y.

so number formed = 10y+x

Number obtained after reversing the digits = 10x+y

$→7(10y+x)=4(10x+y)→70y+7x=40x+4y→66y=33x→2y−x=0.....(i)→x−y=3......(ii) < /p > < p >→7(10y+x)=4(10x+y)→70y+7x=40x+4y→66y=33x→2y−x=0.....(i)→x−y=3......(ii)</p><p>$

y = 3

from equation (ii) we will find the equation of x

x= 6

therefore the number is 36.

________________________

Question

The sum of a two digit number and the number obtained by reversing the order of its digits is 99. If the digits differ by 3, find the number.

Solution

Assume the ones digit as x and tens digit as y.

so number formed = 10y+x

Number obtained after reversing the digits = 10x+y

10y+ x+ 10x+ y= 99

11x + 11y= 99

x+y = 9 .......(i)

x-y= 3 ........(ii)