Seven times a two-digit number is equal to four times the number obtained by reversing the order of its digit. if the difference between the digits is 3, then find the number.
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9
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Seven times a given two digit number is equal to four times the number obtained by inter changing the digits
7(10x+y)=4(x+10y)
70x+7y=4x+40y
66x-33y=0
2x-y=0
2x=y
The difference of the digits is 3
y-x=3
2x-x=3
x=3
y=6
that number is 36.
Answered by
4
Answer:
36
Step-by-step explanation:
Let the unit digit be a and tenth unit be b .
So , number = 10 b + a
It's said number is seven times is equal to reversing the order of its digit.
= > 7 ( 10 b + a ) = 4 ( 10 a + b )
= > 70 b + 7 a = 40 a + 4 b
= > 66 b = 33 a
= > a = 2 b ... ( i )
Also given numbers' difference is 3 .
a - b = 3 ( ii )
From ( i ) and ( ii ) we get :
a b - b = 3
b = 3
= > a = 6
Hence number = > 30 + 6
= > 36.
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