Seven times a two digit number is equal to four times the number obtained by reversing the order of it digits. If the difference of the digits is 3, determine the number.
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Let the 1st and 2nd digits no. be y and x respectively.
According to question...
7(10x + y) =4(10y + x)
70x + 7y = 40y + 4x
70x - 4x = 40y - 7y
66x = 33y
y = 2x.......(1)
y - x = 3.....(2) (given in question)
By substitution method......
Put the value of (y) in equation (2)....
y - x = 3
2x - x = 3
(x = 3).....
From eqs. (1), we get..
y = 2x
y = 2(3)
(y = 6)......
Therefore, a two digit number will be
10x + y
10(3) + 6
30 + 6
36.....
And number obtained will be
10y + x
10(6) + 3
60 + 3
63
Since, 63 and 36 is in reversing order.....
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