Question

Seven times a two digit number is equal to four times the number obtained by reversing the order of it digits. If the sum of the digits is 3, determine the number.

Answer 1

No=12 Hope it would help u

Answer 2

$\huge \bf \pink{Hey \: there !! }$

Let the ten's digits of the required number be x.

And, the unit's digit be y.


Then, the number = ( 10x + y ) .

The number obtained by reversing the digits = ( 10y + x ) .


A/Q,

•°• 7( 10x + y ) = 4( 10y + x ) .

=> 70x + 7y = 40y + 4x .

=> 70x - 4x = 40y - 7y .

=> 66x = 33y .

=> 66x - 33y = 0.

=> 33( 2x - y ) = 0.

=> 2x - y = 0.

•°• y = 2x............(1) .


▶ Now, sum of the digits is 3 .

=> x + y = 3 ...............(2) .

[ Putting the value of y ] .

=> x + 2x = 3 .

=> 3x = 3 .

=> x = 3/3 .

•°• x = 1 .


▶ On putting the value of x in equation (2), we get

=> 1 + y = 3 .

=> y = 3 - 1 .

•°• y = 2 .


Therefore, the required number = 10x + y .

= 10 × 1 + 2 .

= 10 + 2 .

$\huge \boxed{ \boxed{ \blue{ = 12.}}}$



✔✔ Hence, the required number is 12 ✅✅.

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