Question

seven times a two digit number is equal to four times the number obtained by reversing the order of its digits.if the difference of the digit is 3,determine the number.

Answer 1

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ANSWER:

Let the two digit number be 10x + y


According to the question,

7(10x+y)=4(10y+x)

70x + 7y =40y + 4x

70x-4x=40y-7y

66x=33y

2x =y

ALSO, it is given that:

y-x=3

2x-x=3(substituting 2x =y)

x=3

ALSO,

2x=y

2(3)=y

6=y

Hence,x=3 and y=6

So,

The two digit number is 36

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Answer 2

Answer:

36

Step-by-step explanation:

Let the unit digit be a and tenth unit be b .

So , number = 10 b + a

It's said number is seven times is equal to reversing the order of its digit.

= > 7 ( 10 b + a ) = 4 ( 10 a + b )

= > 70 b + 7 a = 40 a + 4 b

= > 66 b = 33 a

= > a = 2 b ... ( i )

Also given numbers' difference is 3 .

a - b = 3  ( ii )

From ( i ) and ( ii ) we get :

a b - b = 3

b = 3

= > a = 6

Hence number = > 30 + 6

= > 36.