seven times a two digit number is equal to four times the obtained by reversing the order of its digits. if the difference of the digits is 3, determine the number
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let the original numb be x+10
Number by reversing its order is 10x+y
According to the question
7(10x+y)=4(x+10y)
70x+7y=4x+40y
66x-33y=0
2x-y=0
2x=y
The difference of the digits is 3
y-x=3
2x-x=3
x=3
y=6
that number is 36.
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