Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits. If the difference between the digits is 3. Find the number.
Answers
Answered by
6
Step-by-step explanation:
LET THE DIGIT AT TEN" S PLACE BE X & UNIT"S PLACE BE Y
REQ. ORIGINAL NO. = 10X+Y REVERSED NO. =10Y+X
ALSO Y - X = 3 => Y = 3 +X
A/Q, 7(10X+Y) = 4 (10Y+X)
=> 7( 11X + 3) = 4( 30 +11X)
=>77X -44X = 120 -21
=> 33 X =99
=> X = 3 & Y= 3 +X = 3 +3 = 6
REQ. ORIGINAL NO. = 10X+Y = 10 * 3 +6 = 36...................
Answered by
8
Answer:
36
Step-by-step explanation:
Let the unit digit be a and tenth unit be b .
So , number = 10 b + a
It's said number is seven times is equal to reversing the order of its digit.
= > 7 ( 10 b + a ) = 4 ( 10 a + b )
= > 70 b + 7 a = 40 a + 4 b
= > 66 b = 33 a
= > a = 2 b ... ( i )
Also given numbers' difference is 3 .
a - b = 3 ( ii )
From ( i ) and ( ii ) we get :
a b - b = 3
b = 3
= > a = 6
Hence number = > 30 + 6
= > 36.
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