Seven times of a two-digit number is equal to four times the number obtained by reversing its digit. If the SUM of the digits of the original number is 3,find the number.
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Step-by-step explanation:
When we check the first given condition, 7 times the original number is equal to 4 times the reversed number. 7(36) = 252 = 4(63) Verified. The second condition, the difference between digits 6 – 3 = 3 Verified.
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Answer:
let the number is 10x+y
so,
7(10x+y)=4(10y+x)
=> 70x+7y=40y+4x
=> 70x-4x=40y-7y
=> 66x=33y
=> 66x/33=y
=> 2x=y
again,
x+y=3 ( putting the value of y)
=> x+2x=3
=> 3x=3
=> x=3/3=1
y=2.1=2
the number is 10.x+y=10.1+2=10+2=12
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