Seven times the complement of an angle is 10° less than 3 times its supplement . Find the angle
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let the angle be x, then ATQ
7(90-x) = 3(180-x)-10
630-7x = 540-3x+10
80 = 4x
x = 20
7(90-x) = 3(180-x)-10
630-7x = 540-3x+10
80 = 4x
x = 20
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