Question

Seven years ago Nuri’s age was five times the square of sonu’s age. Three years hence sonu’s age will be two-fifth of Nuri’s age. Find their present ages ?​

Answer 1

Answer:

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Step-by-step explanation:

Let the present age of Nuri  =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10                       ………..(1)

Ten years later,

Age of Nuri  =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10                           ………..(2)

X–3y=−10                        ………..(1)

Subtracting equation (1) from equation (2)  we get

Y=20

Plug this value in equation first we get

X−3∗20=−10

X=60–10

X=50

Hence age  of Nuri =50 years and age of Sonu =20 years