Question

seven years ago the age of a father was five times that of the son. if it is currently only three times how old is each?

Answer 1

Answer:

Step-by-step explanation:

Let the age of father be x

Nd age of son be y

A.T.Q

At present time

x=3y. __________1

Before 7 years

x-7=5 (y-7) __________2

Solving 1 nd 2

3y-7=5y-35

-2y=-28

》y=14

x=3y=3×14=42

Therefore the age of father and son are 42 nd 14 resp.