Question

seven years ago the age of father was seven times his daughter's age.Three years from now father age should be three times his daughter age..find the present age​

Answer 1

Answer:Let the fathers age be x years and his son be y years.

Therefore, seven years ago, age of father =  (x-7)  

and age of son = (y - 7)

According to the given condition,

x-7 =7(y-7)  

or x-7y = -42 ...(1)

After 3 years, fathers age = x+3  and

son's age = (y+3)

As per given condition,

x+3 = 3(y+3)  

x-3y = 6 ...(2)

ON subtracting (2) from (1), we get

x - 7y - (x -3y) = -42 - 6

⇒ -4y = -48

⇒ y = 12

On putting value of y in (2), we get

x - 3(12) = 6

⇒ x = 6 + 36 = 42

Hence, present father's age = 42 years

and present son's age = 12 years.

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