Seven years ago, the combined ages of Anbu and Babu was twice that of Siva. If the sum of the ages of Babu and Anbu, fifteen years hence, is 98 years, what is the present age of Siva?
036
O 34
27
8
31
B
Answers
Answer:
34
Step-by-step explanation:
Let the current ages of Anbu, Babu and Siva be A, B and S respectively
Therefore, seven years ago, their ages were, A - 7, B - 7 and S - 7 respectively.
Then, the statement given "Seven years ago, the combined ages of Anbu and Babu was twice that of Siva" translates into maths equation as
= 2(S - 7)
Combined ages of Anbu and Siva, seven years ago = (A - 7) + (B - 7)
twice the age of Siva, seven years ago = 2(S - 7)
(A - 7) + (B - 7) = 2(S - 7)
=> A + B - 14 = 2S - 14
=> A + B = 2S ----------------- (1)
The other part of the statement says "the sum of the ages of Babu and Anbu, fifteen years hence, is 98 years". This translates into
(B+15) + (A + 15) = 98
=> A + B + 30 = 98
=> A + B = 68
using this in equation (1), we get
68 = 2S
=> S = 34
i.e, the current age of Siva is 34