Seven years ago varun's age was five times the square of swati's age. The three years hence swati's age will be two fifth of varun's age. Find their present ages.
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Answered by
3
Answer:
9 and 27
Step-by-step explanation:
Seven years ago:
Varun's age= 5x^2 -7
Swati's age= x-7
Present age:
Varun's= 5x^2 +7
Swati's= x +7
After three years:
Swati's age=2/5× (5x^2 +7 +3)
=2/5×(5x^2 +10)
= 2x^2 +4
Varun's age= x +7 +3
= x +10
Solving for x:
2x^2 +4 = x +10
2x^2 -x -6 =0
x=2 or x= -1.5
x can't be -1.5 hence it is 2
Present ages:
Swati's:
=x +7
=2 +7
=9
Varun's:
=5x^2 +7
=5×4 +7
=27
Answered by
2
Varun's age =27
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