Question

Seven years ago Varun's age was five times the square of Swati's age. Three years hence Swati's age will be two fifth of Varun's age. Find their present ages.​

Answer 1

Answer:

Solution

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Seven years ago. let Swati's age be x years. Then, seven years ago Varun's age was 5x

2

years.

Swati's present age =(x+7) years, Varun's present age=(5x

2

+7) years

Three years hence, we have

Swati's age (x+7+3) years =(x+10) years

Varun's age =(5x

2

+7+3)=(5x

2

+10)

It is given that three years hence Swati's age wil be

5

2

of Varun's age

∴x+10=

5

2

(5x

2

+10)

⇒x+10=2x

2

+4

⇒2x

2

−x−6=0

⇒2x

2

−4x+3x−6=0

⇒(2x+3)(x−2)=0

⇒x−2=0⇒x=2

Hence Swati's present age =(2+7) years =9 years

Varun's present age =(5×x

2

+7) years =27 years

Step-by-step explanation:

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