Question

Seven years ago Varun’s age was five times the square of Swati’s age. Three

years hence Swati’s age will bek two fifth of Varun’s age. Find their present

ages.

nhi mai yah app delete kar dunga kuch din bad ​

Answer 1

Seven years ago Varun’s age was five times the square of Swati’s age. Three

years hence Swati’s age will be two fifth of Varun’s age. Find their present

Answer 2

Answer:

Seven years ago. let Swati's age be x years. Then, seven years ago Varun's age was 5x^2

years.

Swati's present age =(x+7) years, Varun's present age=(5x^2

+7) years

Three years hence, we have

Swati's age (x+7+3) years =(x+10) years

Varun's age =(5x^2

+7+3)=(5x

2Seven years ago. let Swati's age be x years. Then, seven years ago Varun's age was 5x^2

years.

Swati's present age =(x+7) years, Varun's present age=(5x^2+7) years

Three years hence, we have

Swati's age (x+7+3) years =(x+10) years

Varun's age =(5x^2+7+3)=(5x^2+10)

It is given that three years hence Swati's age wil be 5^2

of Varun's age

∴x+10= 5^2

(5x2+10)

⇒x+10=2x 2+4

⇒2x 2

−x−6=0

⇒2x 2

−4x+3x−6=0

⇒(2x+3)(x−2)=0

⇒x−2=0⇒x=2

Hence Swati's present age =(2+7) years =9 years

Varun's present age =(5×x

2

+7) years =27 years

+10)

It is given that three years hence Swati's age wil be

5

2

of Varun's age

∴x+10=

5

2

(5x

2

+10)

⇒x+10=2x

2

+4

⇒2x

2

−x−6=0

⇒2x

2

−4x+3x−6=0

⇒(2x+3)(x−2)=0

⇒x−2=0⇒x=2

Hence Swati's present age =(2+7) years =9 years

Varun's present age =(5×x^ 2+7) years =27 years