Question

seventy two is divided in to two parts such that twelve time of first added to five times of the second part makes 472 .find the both number.

Answer 1

Solution -

Let's assume one part as x

So, the another part as 72 - x

According to Question,

Given : 12 × One part + 5 × second Part = 472

12(x) + 5(72 - x) = 472

⇒ 12x + 360 - 5x = 472

⇒ 7x + 360 = 472   [By transposition]

⇒ 7x = 472 - 360

⇒ 7x = 112               [By transposition]

⇒ x = 112 / 7​

⇒ x = 16 ​

Required Numbers -

x = 16

72 - x = 72 - 16 = 56

Hence, the required numbers are 16 and 56

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Answer 2

ANSWER :-

16 and 56



EXPLAINATION :-



Let's assume one number be x

And another number be 72 - x


According to Question,


⇒ 12x + 360 - 5x = 472

⇒ 7x + 360 = 472  

⇒ 7x = 472 - 360

⇒ 7x = 112              

⇒ x = 112 / 7​

⇒ x = 16 ​

First number -->

x = 16

So ,

First number = 16


Second number -->

72 - x

72 - 16 = 56

Therefore ,

The required numbers are 16 and 56 .