Question

Several electric bulb are designed to be on 220V electric supply lines are rated at 10W . How many lamps can be connected in parallel with each other across the two wires of 220V line, if the maximum allowed current is 5A ?

Answer 1

Answer:

Explanation: using our knowledge about Power

We get that P = (V^2)/ R

Using this we will find the resistance of one bulb

We get resistance of one bulb to be equal to => 4840 ohm

Now using ohm's law we will find the net resistance in the wire

We get net resistance in the wire to be => 44 ohm

Now according to the question

(4840ohm)/ n = 44 ohm |• it can be derived using the knowledge of parallel resistors•|

N = 110

Points to remember

Ohm's law,

Power =(V^2)/R = (VI) = (I^2)R

Hope you understand.

Answer 2

I=5A

➡️V=220V

➡️P=VI

➡️P=5×220

➡️P=1100W

➡️Power of each bulb=10W

➡️No. of bulb=1100/10=110

➡️➡️Therefore numberof bulb is 110.

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