several electric bulbs designed to be used on a 220 v electric supply line are rated 10 w. how many lamps can be connected in parallel with each other across a 220 v mains line if the maximum allowable current is 5 A
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Answered by
12
Resistance R1 of the bulb is given by the expression,
Supply voltage, V = 220 V
Maximum allowable current, I = 5 A
Rating of an electric bulb P=10watts
Because R=V2/P
R1=220^2/10
=4840
According to Ohm’s law,
V = I R
Let R is the total resistance of the circuit for x number of electric bulbs
R=V/I
=220/5=44 Ω
Resistance of each electric bulb, R1=4840Ω
1/R=1/R1+1/R2+1/R3.........x times
1/R=1/R1*x
x=R1/R=4840/44
∴ Number of electric bulbs connected in parallel are 110.
If this answer helps u then please make it as brainliest
Supply voltage, V = 220 V
Maximum allowable current, I = 5 A
Rating of an electric bulb P=10watts
Because R=V2/P
R1=220^2/10
=4840
According to Ohm’s law,
V = I R
Let R is the total resistance of the circuit for x number of electric bulbs
R=V/I
=220/5=44 Ω
Resistance of each electric bulb, R1=4840Ω
1/R=1/R1+1/R2+1/R3.........x times
1/R=1/R1*x
x=R1/R=4840/44
∴ Number of electric bulbs connected in parallel are 110.
If this answer helps u then please make it as brainliest
Gurupandey:
can u explai R1=220^2/10
Answered by
4
Explanation:
Resistance R1 of the bulb is given by the expression,
Supply voltage, V = 220 V
Maximum allowable current, I = 5 A
Rating of an electric bulb P=10watts
Because R=V2/P
According to Ohm’s law,
V = I R
Let R is the total resistance of the circuit for x number of electric bulbs
R=V/I
=220/5=44 Ω
Resistance of each electric bulb, R1=4840Ω
∴ Number of electric bulbs connected in parallel are 110.
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