Question

sgh
$4 sin ^{2} 60 + 3 \cos {}^{2} 60$

Answer 1

$3 { (\sin(60)) }^{2} + {( \sin(60) )}^{2} + 3{( \cos(60)) }^{2} \\ = > 3( { \sin(60) }^{2} + { \cos(60) }^{2} ) + { \sin(60) }^{2} \\ = > 3 \times 1 + { (\sqrt{3} \div 2) }^{2} \\ = > 3 + (3 \div 4) \\ = 15 \div 4$
another way is to put the value of sin (60) and cos (60)