Question

Sh Show that :sin 90°=2 cos 45°sin 45°

Answer 1

sin 90° = 1
2×cos45°×sin45°
= 2×(1/√2)×(1/√2) (since sin45 and cos45 are (1/√2)

= 2×(1/2)
= 1.
hence RHS=LHS

Answer 2

LHS
Sin90 = 1

RHS
Cos45= 1/√2
Sin45=1√2
2 x 1/√2 x 1/√2
2 x 1/2
1

Hence, LHS=RHS