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The coach of a cricket team buys 3 bats and 6 balls for 3900. Later, she buys and
bat and 3 more balls of the same kind for 1300. Represent this situation algebraic
and geometrically
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let rate of bat = xRs.
and rate of ball = yRs.
3x+6y=3900.....(i)
and x+3y=1300.....(ii)
or x=(1300−3y)
now equation (i) can be written as
3(1300−3y)+6y=3900
3900−9y+6y=3900
∴y=0
Ans:- x=1300
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