शेजारील आकृती 1.14 मध्ये रेख PS लंब रेख RQ रेख QT लंब रेख PR. जर RQ =6,PS=6,PR=12, तर QT काढा
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Our question is: शेजारील आकृती 1.14 मध्ये रेख PS लंब रेख RQ रेख QT लंब रेख PR. जर RQ =6,PS=6,PR=12, तर QT काढा
Since we want to know what is the value of x and y when, 39x52 + 278y = y2y3x.
In the equation that is given to us, the first digit of each number is 2 then y and x.
Hence, x = y+2
Thus, the sum of the second digits is 5+8= 13 which gives us the information that 1 is carry forwarded to next digit.
x + 7 + 1 = 10 + y and 1 is carried once more.
Then:
9 + 2 + 1 = 12 and 1 is carried once more.
Now last digit is 3 and only carry forwarded term 1, thus:
3 + 1 = y
⇒ Y = 4
Since x = y+2, we have:
x = 4 + 2
⇒ x = 6
Hence, our solution is x = 6 and y = 4.
I hope this helps you!!
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