Math, asked by chandreshthakre20, 3 months ago

शून्यक ज्ञात कीजिए
x2-2x-8

Answers

Answered by Aukatkbahar
6

Answer:

x²- 2x - 8

x²+2x-4x-8

x(x+2) -4(x+2)

(x-4) (x+2)

Thus when we compare both of it with 0 we get:

x = 4

x = -2

Hope it helpful to uh

Answered by ad0308
10

Answer:

 {x}^{2}  - 2x - 8 \\  {x }^{2}  - (4 - 2)x -8 \\  {x}^{2} - 4x + 2x - 8 \\  x(x - 4) + 2(x - 4) \\ (x - 4)(x + 2) \\ x - 4 = 0 \\ x = 4 \\ x + 2 = 0 \\ x =  - 2

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